Ratio Proportion & Variation
Concepts (2)
Master direct (y=kx) and inverse (y=k/x) variation for SSC CGL. Focus on quick ratio/product methods to solve problems involving proportionality constants efficiently.
Core Formula
Variation describes how one quantity changes in relation to another. For SSC CGL, understanding direct and inverse variation is crucial for quick problem-solving.
1. Direct Variation: When two quantities, say x and y, vary directly, it means that as x increases, y increases proportionally, and vice-versa. Their ratio remains constant.
Formula: y ∝ x or y = kx
Where k is the constant of proportionality.
2. Inverse Variation: When two quantities, say x and y, vary inversely, it means that as x increases, y decreases proportionally, and vice-versa. Their product remains constant.
Formula: y ∝ 1/x or y = k/x
Where k is the constant of proportionality.
Worked Example 1 (Direct Variation)
Question: If A varies directly as B, and A = 15 when B = 5, what is the value of A when B = 8?
Solution:
- Identify Variation Type: Direct Variation (A ∝ B).
- Write Formula: A = kB
- Find 'k': Use the given values (A=15, B=5): 15 = k * 5 k = 15 / 5 = 3
- Solve for New Value: Use
k=3andB=8: A = 3 * 8 A = 24
Worked Example 2 (Inverse Variation)
Question: If X varies inversely as Y, and X = 12 when Y = 4, what is the value of X when Y = 6?
Solution:
- Identify Variation Type: Inverse Variation (X ∝ 1/Y).
- Write Formula: X = k/Y
- Find 'k': Use the given values (X=12, Y=4): 12 = k / 4 k = 12 * 4 = 48
- Solve for New Value: Use
k=48andY=6: X = 48 / 6 X = 8
Shortcuts & Tricks
For competitive exams, avoid finding 'k' explicitly every time. Use the ratio method:
- Direct Variation: If
y1 = kx1andy2 = kx2, theny1/x1 = y2/x2. This meansy1/y2 = x1/x2.- Example 1 Shortcut: A1/B1 = A2/B2 => 15/5 = A2/8 => 3 = A2/8 => A2 = 24.
- Inverse Variation: If
y1 = k/x1andy2 = k/x2, theny1x1 = y2x2.- Example 2 Shortcut: X1Y1 = X2Y2 => 12 * 4 = X2 * 6 => 48 = 6X2 => X2 = 8.
Common Mistakes
- Misidentifying Variation Type: Confusing direct with inverse variation, leading to incorrect formula application.
- Calculation Errors: Simple arithmetic mistakes when finding 'k' or solving for the unknown value.
- Ignoring Units: While less common in basic variation problems, always be mindful of units in more complex applications.
- Not Using Shortcuts: Wasting time by always calculating 'k' when a direct ratio/product method is faster.
Derivation (brief)
The concept of variation stems from proportionality. When we say y is proportional to x (y ∝ x), it implies that the ratio y/x is constant. This constant is denoted by k, the constant of proportionality. Thus, y/x = k, which rearranges to y = kx. Similarly, for inverse proportionality, y ∝ 1/x implies that the product y * x is constant, leading to yx = k or y = k/x. This k is unique for a given relationship between variables and allows us to predict values.
Advanced Examples
1. Joint Variation: When a quantity varies directly as two or more other quantities, it's joint variation. If A varies directly as B and C, then A = kBC.
Question: If P varies directly as Q and inversely as R, and P = 10 when Q = 5 and R = 2, find P when Q = 8 and R = 4.
Solution:
- Identify Variation Type: Joint variation (P ∝ Q/R).
- Write Formula: P = k * (Q/R)
- Find 'k': Use initial values (P=10, Q=5, R=2): 10 = k * (5/2) k = 10 * (2/5) = 4
- Solve for New Value: Use
k=4,Q=8,R=4: P = 4 * (8/4) P = 4 * 2 P = 8
2. Combined Variation: Involves both direct and inverse variation simultaneously.
Variation Types
- Direct Variation:
y = kx(e.g., cost of items and number of items) - Inverse Variation:
y = k/x(e.g., time taken to complete work and number of workers) - Joint Variation:
y = kxz(e.g., volume of a cylinder varies jointly as its height and the square of its radius, V = khr²) - Partial Variation: A quantity varies partly directly and partly inversely, or partly constant and partly directly (e.g.,
y = a + bx). This is less common in basic SSC CGL problems but good to know.
Time-Saving Methods
For complex problems involving multiple variables (joint variation), the ratio method can be extended:
If A = k * (B/C):
(A1 * C1) / B1 = (A2 * C2) / B2 (since both sides equal k)
- Advanced Example Shortcut: (P1 * R1) / Q1 = (P2 * R2) / Q2 (10 * 2) / 5 = (P2 * 4) / 8 20 / 5 = P2 / 2 4 = P2 / 2 P2 = 8
This method bypasses finding k and directly sets up a proportion, saving crucial time during the exam.
Ratio & Proportion defines relationships between quantities. Master direct, inverse, compound ratios, and proportion types (mean, third, fourth) for quick problem-solving in SSC CGL.
Ratio & Proportion is fundamental for SSC CGL, forming the base for many other topics like mixtures, ages, and time & work. Speed and accuracy here are critical.
Core Formulas
-
Ratio: A comparison of two quantities of the same unit. Represented as
a:bora/b. Always simplify to lowest terms.- Duplicate Ratio:
a^2:b^2 - Sub-duplicate Ratio:
√a:√b - Triplicate Ratio:
a^3:b^3 - Sub-triplicate Ratio:
∛a:∛b - Compounded Ratio: The ratio of the product of antecedents to the product of consequents. For
a:b,c:d,e:f, the compounded ratio is(a*c*e) : (b*d*f)or(a/b) * (c/d) * (e/f).
- Duplicate Ratio:
-
Proportion: An equality of two ratios. If
a:b = c:d, thena, b, c, dare in proportion, written asa:b::c:d. This impliesad = bc(product of extremes = product of means).- Mean Proportional between
aandb:√(ab) - Third Proportional to
aandb:b^2/a(assuminga:b::b:x, wherexis the third proportional) - Fourth Proportional to
a, b, c:bc/a(assuminga:b::c:x, wherexis the fourth proportional)
- Mean Proportional between
-
Componendo & Dividendo (C&D): If
a/b = c/d, then(a+b)/(a-b) = (c+d)/(c-d). This is a powerful shortcut for equations involving fractions.
Worked Example 1
Q: If A:B = 3:4 and B:C = 8:9, find A:B:C and the compounded ratio of A:B and B:C.
Solution:
- Find A:B:C: To combine ratios, make the common term (B) equal.
A:B = 3:4(multiply by 2) =>A:B = 6:8B:C = 8:9So,A:B:C = 6:8:9 - Compounded Ratio:
(A/B) * (B/C) = (3/4) * (8/9) = (3*8)/(4*9) = 24/36 = 2/3. So,2:3.
Worked Example 2
Q: Find the mean proportional between 16 and 25, and the fourth proportional to 4, 12, and 15. Solution:
- Mean Proportional: For 16 and 25,
√(16 * 25) = √(400) = 20. - Fourth Proportional: For 4, 12, 15, let the fourth proportional be
x.4:12::15:x=>4x = 12 * 15=>x = (12 * 15) / 4=>x = 3 * 15 = 45.
Shortcuts & Tricks
- Combining Ratios (A:B, B:C): Write
A:B:C. MultiplyAbyB's second value,Bby bothBvalues,CbyB's first value. Example:A:B = 2:3,B:C = 4:5.A:B:C = (2*4) : (3*4) : (3*5) = 8:12:15. - Direct Proportional Formulas: Memorize
√(ab),b^2/a,bc/afor mean, third, and fourth proportional respectively. This saves significant time. - Componendo & Dividendo: When you see
(x+y)/(x-y)or similar structures, immediately think C&D. It simplifies complex fractional equations rapidly.
Common Mistakes
- Confusing Proportional Types: Students often mix up mean, third, and fourth proportional formulas. Remember: Mean (two terms, middle term), Third (two terms, third term in continuous proportion), Fourth (three terms, fourth term).
- Incorrectly Combining Ratios: Not making the common term equal before combining can lead to errors. Always ensure the value for the common element is consistent across all ratios.
- Calculation Errors: Simple arithmetic mistakes in multiplication or division are common. Practice mental math and cross-check calculations, especially with large numbers or fractions.
Ready to practice? Start an interactive lesson.
Start Lesson: Direct & Inverse Variation